a ) \(\frac{x}{3}-\frac{10}{21}=-\frac{1}{7}\)

\(\frac{x}{3}=-\frac{1}{7}+\frac{10}{21}\)

\(\frac{x}{3}=-\frac{3}{21}+\frac{10}{21}\)

\(\frac{x}{3}=-\frac{13}{21}\)

\(x:3=-\frac{13}{21}\)

\(x=-\frac{13}{21}.3\)

Giải:

Theo bài ra ta có:

\(\frac{-5}{6}+\frac{8}{3}+\frac{29}{-6}\le x\le\frac{-1}{2}+2+\frac{5}{12}\)

\(\Rightarrow-3\le x\le\frac{23}{12}\)

\(\Rightarrow x\varepsilon\left\{-2;-1;0;1\right\}\)

\(\frac{-5}{6}+\frac{16}{6}+-\frac{29}{6}\le x\le\frac{-6}{12}+\frac{24}{12}+\frac{5}{12}\)

=>-3\(\le\) x\(\le\) 23/12

=> x thuộc{-2-1;0;1}

x thuộc {-2;-1;0;1}

Đề bài thiếu : \(x\inℤ\)

Ta có : 

\(\frac{-5}{6}+\frac{8}{3}+\frac{-29}{6}\le x\le\frac{-1}{2}+2+\frac{5}{2}\)

\(\Leftrightarrow\)\(\frac{-5+16-29}{6}\le x\le\frac{-1+4+5}{2}\)

\(\Leftrightarrow\)\(\frac{-18}{6}\le x\le\frac{8}{2}\)

\(\Leftrightarrow\)\(-3\le x\le4\)

\(\Rightarrow\)\(x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)

Vậy \(x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)

Chúc bạn học tốt ~ 

\(a,\left(\frac{31}{20}-\frac{26}{45}\right)\cdot\left(\frac{-36}{35}\right)< x< \left(\frac{51}{56}+\frac{8}{21}+\frac{1}{3}\right)\cdot\frac{8}{13}\)

\(taco:\left(\frac{31}{20}-\frac{26}{45}\right)\cdot\left(\frac{-36}{35}\right)=\frac{35}{36}\cdot\frac{-36}{35}=-1\)

\(\left(\frac{51}{56}+\frac{8}{21}+\frac{1}{3}\right)\cdot\frac{8}{13}=\frac{13}{8}\cdot\frac{8}{13}=1\)

\(=>x=0\)

\(b,\frac{-5}{6}+\frac{8}{3}+\frac{29}{-3}< x< \frac{-1}{2}+2+\frac{5}{2}\)(dau <co dau gach ngang o duoi nha)

\(taco:\frac{-5}{6}+\frac{8}{3}+\frac{29}{-3}=\frac{-5}{6}+\frac{8}{3}+\frac{-29}{3}=\frac{-5}{6}+\frac{16}{6}+\frac{-58}{6}=\frac{-47}{6}=-7,8\)

\(\frac{-1}{2}+2+\frac{5}{2}=\frac{3}{2}+\frac{5}{2}=4\)

tu do \(=>x=-7,8;...;0;1;2;3;4\)
 

=> -3</ x </ 4

=> x thuộc { -3; -2; -1; 0; 1; 2; 3; 4}

mình cần gấp nhé

Ta có : \(-\frac{5}{6}+\frac{8}{3}+\frac{29}{-6}=-3\) và \(\frac{1}{2}+2+\frac{5}{2}=5\)

Vậy -3 < x < 5. Do x \(\in\) Z nên x \(\in\) {-2; -1; 0; 1; 2; 3; 4}